中文XML论坛--[求助]最近在网上看到不少关于解析XML的例子,但例子的XML都是简单的那种,复杂的如何处理?

贴子主题： [求助]最近在网上看到不少关于解析XML的例子,但例子的XML都是简单的那种,复杂的如何处理?

本主题类别:

下面的程序只能提取如<xxx>YYYY</xxx>中xxx的内容和YYYY的内容.对于
<Envelope type="request" ConnectionType=“short” ClientID=”身份证编号”>中ConnectionType=“short”无法解析.请问有何方法?(偶刚学XML,一般用到啥就找啥,太深了也理解不上)请大家帮看看,谢谢!!!!!

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import java.io.*;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
import org.w3c.dom.NamedNodeMap;

public class OrderProcessor
{
   private static void stepThroughAll(Node start)
   {
      System.out.println(start.getNodeName() + " = " + start.getNodeValue());
      if(start.getNodeType() == start.ELEMENT_NODE)
      {
         NamedNodeMap startAttr = start.getAttributes();
         for(int i = 0; i < startAttr.getLength(); i ++ )
         {
            Node attr = startAttr.item(i);
            System.out.println("   Attribute: " + attr.getNodeName() + " = " + attr.getNodeValue());
         }
      }
      for(Node child = start.getFirstChild(); child != null; child = child.getNextSibling())
      {
         stepThroughAll(child);
      }
   }
   private static void stepThrough(Node start)
   {
      System.out.println(start.getNodeName() + " = " + start.getNodeValue());
      for(Node child = start.getFirstChild(); child != null; child = child.getNextSibling())
      {
         stepThrough(child);
      }
   }
   public static void main(String args[])
   {
      File docFile = new File("Text.xml");

      Document doc = null;
      try
      {
         DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
         DocumentBuilder db = dbf.newDocumentBuilder();
         doc = db.parse(docFile);
         Element root = doc.getDocumentElement();
         System.out.println("The root element is " + root.getNodeName());
         NodeList children = root.getChildNodes();
         System.out.println("There are " + children.getLength() + " nodes in this document.");
         //      stepThrough(root);
         stepThroughAll(root);
         for(Node child = root.getFirstChild(); child != null; child = child.getNextSibling())
         {
            System.out.println(child.getNodeName() + " = " + child.getNodeValue());
         }
      }
      catch(Exception e)
      {
         System.out.print("Problem parsing the file: " + e.getMessage());
      }
   }
}


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